Conduit Fill Practice for the California Electrician Exam
Conduit fill checks that the wires don't take up more of the pipe than code allows, so they can shed heat. On the California exam, calculations are part of the Determination of electrical system requirements domain. Here is the pattern, one worked example, and a question to try.
Last reviewed June 2026
One worked example
Five 12 AWG THHN run in 1-inch EMT. Are you under the fill limit?
- 1Name the problem
This is a conduit fill. Bundle too many wires and they cannot shed heat, so code caps how much of the pipe the conductors can take up.
- 2Add up the conductor area
Each conductor takes a fixed area from Chapter 9 Table 5. Add them all together.
5 × 12 AWG THHN = 0.0665 sq in
Subtotal: 0.0665 sq in (5 conductors)
- 3Find the allowed fill
Table 1 sets the cap by how many conductors are in the pipe. One conductor 53%, two 31%, three or more 40%.
5 conductors → 40% allowed
Raceway area (Table 4): 0.864 sq in
Allowed = 0.864 × 0.40 = 0.3456 sq in
- 4Compare
Your conductors fill 7.70% of the pipe. The raceway has room. You are under the limit.
0.0665 sq in vs 0.3456 sq in allowed
Now try one
Your turn. Nine 12 AWG THHN in 1/2-inch EMT.
What percent of the pipe do they fill?
- 1Compare
Your conductors fill 39.38% of the pipe. The raceway has room. You are under the limit.
0.1197 sq in vs 0.1216 sq in allowed
Train it on the platform
Check every domain in 15 minutes.
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