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Conduit Fill Practice for the California Electrician Exam

Conduit fill checks that the wires don't take up more of the pipe than code allows, so they can shed heat. On the California exam, calculations are part of the Determination of electrical system requirements domain. Here is the pattern, one worked example, and a question to try.

Last reviewed June 2026

One worked example

Five 12 AWG THHN run in 1-inch EMT. Are you under the fill limit?

  1. 1
    Name the problem

    This is a conduit fill. Bundle too many wires and they cannot shed heat, so code caps how much of the pipe the conductors can take up.

  2. 2
    Add up the conductor area

    Each conductor takes a fixed area from Chapter 9 Table 5. Add them all together.

    5 × 12 AWG THHN = 0.0665 sq in

    Subtotal: 0.0665 sq in (5 conductors)

  3. 3
    Find the allowed fill

    Table 1 sets the cap by how many conductors are in the pipe. One conductor 53%, two 31%, three or more 40%.

    5 conductors → 40% allowed

    Raceway area (Table 4): 0.864 sq in

    Allowed = 0.864 × 0.40 = 0.3456 sq in

  4. 4
    Compare

    Your conductors fill 7.70% of the pipe. The raceway has room. You are under the limit.

    0.0665 sq in vs 0.3456 sq in allowed

Now try one

Your turn. Nine 12 AWG THHN in 1/2-inch EMT.

What percent of the pipe do they fill?

  1. 1
    Compare

    Your conductors fill 39.38% of the pipe. The raceway has room. You are under the limit.

    0.1197 sq in vs 0.1216 sq in allowed

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